b^2=2b+15

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Solution for b^2=2b+15 equation:


Simplifying
b2 = 2b + 15

Reorder the terms:
b2 = 15 + 2b

Solving
b2 = 15 + 2b

Solving for variable 'b'.

Reorder the terms:
-15 + -2b + b2 = 15 + 2b + -15 + -2b

Reorder the terms:
-15 + -2b + b2 = 15 + -15 + 2b + -2b

Combine like terms: 15 + -15 = 0
-15 + -2b + b2 = 0 + 2b + -2b
-15 + -2b + b2 = 2b + -2b

Combine like terms: 2b + -2b = 0
-15 + -2b + b2 = 0

Factor a trinomial.
(-3 + -1b)(5 + -1b) = 0

Subproblem 1

Set the factor '(-3 + -1b)' equal to zero and attempt to solve: Simplifying -3 + -1b = 0 Solving -3 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1b = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1b = 0 + 3 -1b = 0 + 3 Combine like terms: 0 + 3 = 3 -1b = 3 Divide each side by '-1'. b = -3 Simplifying b = -3

Subproblem 2

Set the factor '(5 + -1b)' equal to zero and attempt to solve: Simplifying 5 + -1b = 0 Solving 5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1b = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1b = 0 + -5 -1b = 0 + -5 Combine like terms: 0 + -5 = -5 -1b = -5 Divide each side by '-1'. b = 5 Simplifying b = 5

Solution

b = {-3, 5}

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